Prob Gaussians exceed eachother
Probability $X > 3Y$ when they are iid Gaussians.
Solution
Since they are both mean 0 and Gaussians are symmetric about their mean, this probability is $1/2$.
Probability $X > 3Y$ when they are iid Gaussians.
Since they are both mean 0 and Gaussians are symmetric about their mean, this probability is $1/2$.